Question

motes the length of the art of a circle of adm 25 -9.5 meters a-3 radians out A) 0.32 m 3) 155m Without graphing the function, determine its amplitude or periode Find the period i 26) y n sin 3x 03.1m D32 A) 5 27) y 3 in Find the amplitude D2 A) 3 C) 3 D2 Use identities to find the act value of the indicated t 28) sin .co 0- Find tan gonometric function of the acute angle o function B) 3 Convert the angle in radians to deerees Emress the answer in decimal form, rounded 29) 7.63 A) 36.66 B) 0.13 C) 437.17 wwer in decimal form, rounded to two decimal places D) 0.28 Find the lengths. Round the answer to three decimal places. 30) A) 3.063 B) 3.403 ft 2.722 it D) 3.7431 Use the reference angle to find the exact value of the expression. Do not use a calculator 31) tan 9300 B) 3 D) - 5 32) tan 5 B) 3

Answer 1

Sol" 25 al eng @ Centen o If Given arc length() = 9.3 meter = 3radians 14=? a s mes wied in radians then aic length (s) = 0 0 9-3 = 3.94 =) = 9.3 => 104 = 3.1 meter)

Given function y=sin (50) . Find period period of a form asin (bx-c)td is 21 campaining values a=15 b=5 ;(- o d =0 1b 2 = period = 21 - 2

@7) Given funcion Y=3Sin z amplitude of a fom asin(bx €)+d wis 101 then com parning vaucle of frien durctly | Q=3 ; b=1 ) = 0 ; C =0 =) cumplitude = lal = 131 = 3 Me (28) To find acute angle o wing given identities sine = 15 , caso = 2/3 find fan as we know tano= sino ose Jomo = vo (29) As we know 1 = 1/180° radian - 1 rac - 180° 5 d (degrees ) = x (sreuclion) *180%a hiven 7 •63 radian =) <(degrees) = 7.63 x 180° =1436-667

Is 1650 344 find arc lengthis) If o given in degrees then cumclength G) = 2 X277 65° 360 .x2a (3 ft) 15 = 3.403 ++) (31) tan 930° Remove full rotatrons of 360 untill the angles is betw een oo and 360° >> tan (330%) = Han (2109) Apply the refference angle by finding angle with equivalent trig values in the first quadront | dansol = 3 (32) tan (5) as we know tanex) = -tan (0) 5) - fan (5) Apply the setterenie angle by finding the angles with canivalent tig values in the first quadrant make the expression negative becuse tangent as negative in the second quachant (-)(-)