Scenario: IP Address: 192.168.1.0 Subnet Mask: 255.255.255.? What is the subnet mask need to be if we want to break up the IP Address space into 4 separate networks??
Scenario: IP Address: 192.168.1.0 Subnet Mask: 255.255.255.? What is the subnet mask need to be if...
Given an IP address and mask of 192.168.1.0 255.255.255.0 (address / mask) subnet A has 55 hosts subnet b has 112 hosts The 0th subnet is not used. (Do not use 192.168.1.0) (Subnetting Help) Subnet A Specification Student Input Number of Network bits in the subnet mask New Subnet mask (decimal) Number of usable hosts IP Subnet (Network ID) First IP Host address Last IP Host address (Subnetting Help) Subnet B Specification Student Input Number of Network bits in the...
Part 1: Develop the IPV4 Addressing Scheme Given an IP address and mask of 192.168.1.0 /24 (address / mask), design an IP addressing scheme that satisfies the following requirements Subnet Number of Hosts Subnet A 20 Subnet B 60 Use subnet zero for the first subnet. No subnet calculators are allowed Host computers will use the last IP address in the subnet. The network router will use the first usable host address. The switch will use the second usable host...
Given the following IP address and subnet mask, what is the network identifier? • IP Address: 18.132.219.175 . Subnet Mask: 255.255.248.0 Network ID: BLANK-1 BLANK-1 Add your answer Question 28 Given the following IP address and subnet mask, what is the network identifier? - IP Address: 18.132.219.175 . Subnet Mask: 255.255.248.0 • Broadcast Address: BLANK-1 BLANK-1 Add your answer
Given an IP address and mask of 192.168.10.0/24 255.255.255.0 (address / mask) subnet A has 100 hosts subnet b has 50 hosts Specification Subnet A Subnet B Number of bits in the subnet IP mask (binary) New IP mask (decimal) Maximum number of usable subnets (including the 0th subnet) Number of usable hosts per subnet IP Subnet First IP Host address Last IP Host address Description Subnet A Subnet B First IP address Last IP address Maximum number of hosts
Network IP Addressing Network Layout of 2 networks Given an IP address and mask of 172.23.29.0/24, design an IP addressing scheme that satisfies the following requirements. Subnet B Specification This network requires space for 62 machines plus the router Number of bits in the subnet Blank 1 IP mask (binary) Blank 2 New IP mask (decimal) Blank 3 Maximum number of usable subnets of this size when using this mask (including the 0th subnet) Blank 4 Number of usable hosts...
using the information given below . what is the ip address , subnet mask , default gateway? ** corrections # of bits in subnet for A :6 # of bits in submet for B: 3 PC-A R1 G0/0 R GO/1 S1 PC-B ? assign the IP ADDRESS information with given information Given, IP address: 202.44.66.0/24 For Subnet A: It needs 2 valid hosts 2 valid hosts + 2 (network and broadcast) = 22 i.e., It needs 2 bit as host...
(a) What is the network number of the IP address 140.100.120.02 if the subnet mask is 255.255.224.0? (b) Does it make sense to have a subnet mask equal to 255.255.224.7? why or why not? (c) Suppose an organization needs 8000 IP addresses. How many Class C addresses would be needed? If they were consecutive, describe the CIDR addressing scheme.
2. Given the IP address 17.119.47.72, apply Subnet Mask 1 and answer the following questions. [2 marks] My subnet mask is: a. What is the subnet address? b. What is the broadcast address for this subnet? Given the IP address 17.119.47.72, apply Subnet Mask 1 and answer the following questions. [2 marks] My subnet mask is: 255.240.0.0 a. What is the subnet address? * What is the broadcast address for this subnet?
Network Subnetting 3 1. Given an IP address of 210.21.21.21 and a subnet mask of 255.255.252.0, what is the address of the network? And the broadcast address? Show your calculation. 2. On a network with an IP address of 155.155.155.155 and a subnet mask of 255.255. 248.0 what is the network ID? And the broadcast address? Show your calculation.
Subnet the above IP addresses..the solution should contain the following: the increment the subnet mask the number of networks the number of hosts. . (C) 200.1./.0, BREAK INTO 40 NETWORES 2. (e) 199.9.10.0, BREAK INTO 14 NETWORKS 3. (B) /70. 50.O.0, BREAK INTO /O00 NETWORES 4. CA /2.0.0.0, BREAK INTO 25 NETWORES . (C) 200.1./.0, BREAK INTO 40 NETWORES 2. (e) 199.9.10.0, BREAK INTO 14 NETWORKS 3. (B) /70. 50.O.0, BREAK INTO /O00 NETWORES 4. CA /2.0.0.0, BREAK INTO 25...