Question

Problem 31.11-Enhanced -with Feedback 3 of 9 Part A A 10-cm-diameter parallel-plate capacitor has a 1.0 mm spacing. The electric field between the plates is increasing at the rate 1.1105 What is the magnetic field strength on the axis? Express your answer to two significant figures and include the appropriate units. You may want to reviow Pages 894 -888) VCorrect Here we leam how to calculate the magnetic field induced in the circular capacitor on its axis Part B What is the magnetic field strength 3.3 cm from the axis? Express your answer to two significant figures and include the appropriate units. B 2.8.10-1 T Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining You have found that a changing electric field does not induce a magnetic field, but that is not the case. Recall how it is distributed inside the ciroular capacitor and how it is calculated. Use Ampere's law Part C What is the magnetic field strength 6.6 cm from the axis? Express your answer to two significant figures and include the appropriate units

Answer 1

contourintegral B-dl vector = mu_0 epsilon_0 d phi_E/dt C = 1/squareroot mu_0 epsilon_0 mu_s epsilon_s = 1/c^2 for r = 3.3 cm d phi_E/dt = 1.1 times 10^6 times pi (0.033)^2 = 3.76 times 10^4 V m/s B middot 2 pi r = 1/c^2 d phi_E/dt B = 1/(3 times 10^8)^2 times 3.76 times 10^4/2 pi (0.033) B = 2.017 times 10^-13 T B middot 2 pi (0.066) = 1/c^2 times 1.1 times 10^6 times pi (0.05)^2 B = 2.315 times 10^-13 T