Question

PROBLEMS 231 PROBLEMS 1. Determine the flow into or out of each reservoir in the pipe system shown in Fig. A, using the Manning diagram with n = 0.011. 2. Determine the flow into or out of each reservoir in the pipe system shown in Fig. B, using the Hazen-Williams diagram with Ci 120. 3. If in Fig. B pipe 3 is closed off by a valva at X, determine the amount and direction of flow in pipes 1, 2, and 4. y El. 100 a. 50 (12. gmnt els 3000 of 6º Fig. A

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Answer 1

Solution Hoy El=100 4000' of 12' ĆEL=80 code 6 ELE SO 5000'076" el 3000 of 8" lo. EI=o As from manning Equation, va Ķ Rn213 s'[K=1.486 for us V = 1.486 R 213 slz Vis in ft/s ne Manning's coefficient. = Given coord) Rn= hydraulic Repuius cross-section Area Wutted perimeter T/4D2 Le Do Rn=0/4 s = slope of Energy line which is equal to=ht circular pipe) TTD :

v= 1.41826 43% (wy y z V= 135.09 (23% ( 13 ) 2 hy/= yx Ll : 72 135.09 / 3 = hto =/V2² * 135.09(0)4323 Table 1 (2/4) From Length Diameter (ats 1st = (2) A-J 4000' la -5 | 3000' 10.67' c-J 5000 1/2 Inov 2² 1135.09 (0%)43] 631241 INH, = 0.219 V, 2 157.77 Inta=0.3+2 V22 70.71' Int=0.690 v32 0.766' 0.630' 10.5'

6. 219 Applying Bernoulli's Equation, Ang ELA ELI = hti 100'- 0' = 0.219 1,2 Viss 100 = 21:36 5H/s V, - Q =) Q = V, XA, = 24.36 x * D, 2 = 21:36 * Ę X12 = 16.7873 [Q,= 16.78 ++/] Ans Applying Bernoullis Equatias 8-5. ELB - Elg = nja 80'-o'= 0.312 V₂2 = V2 = √256.41=16. Oltys N2 = Q2 Q2 = V2 A2 = 16.01* D2 . O2 = 16.0L XTI XC0.672) Jos = 5.644 ++ 3% Aus : Applying Bernoulli's squatten C-s ELL- Elg=ht 50'- 0's 0.690 v32 =) V3 = 150 = 8.5131415 A2 ✓ 0.690 V3 = Q3 5) Q3 = V3 · A3 = 8.513 * Ex Dz? = 8.513x x 0.52 1 03 = 1.67 % Ans