Homework Answers
Answer 17) 1.69 × 10-10 is the Ksp of AgCl.
Explanation:
Write the solubility equilibria for silver chloride as follows:
AgCl(s) --> Ag+(aq) + Cl-(aq)
As AgCl is converting to one ion each of silver and chloride. Therefore, the solubility of silver and chloride ion is same as the solubility of AgCl. Solubility = [Ag+] = [Cl-]
Write the expression for Ksp for the above reaction .
Ksp = [Ag+][Cl-]
Ksp = (0.000013)(0.000013) = 1.69 × 10-10
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