Question

Suppose a graduate student is studying a population of bluebonnets along a roadside. The plants in this population are genetically variable. She counts the seeds produced by 100 plants and measures the mean and variance of seed number. The variance is 30 . Selecting one plant, the student takes cuttings from it and cultivates them, producing many genetically identical clones. She then transplants these clones into the roadside population, allows them to grow for one year, and then counts the number of seeds produced. The student finds that the variance in seed number among the cloned plants is 10 . From the phenotypic variance (VP) of the genetically variable and genetically identical plants, calculate the broad‑sense heritability (H2) of seed number for the roadside population of bluebonnets.

H2=0.67 (wrong)

Answer 1

s soluto Broad rense heritability value 4² z Ve Genetic variation Vp khenotypic variation Initial seeds collected from /ooplants, haning variance - 30 After cole cloning the smiler or single plant pure dire, get variance = 10 Here genetically identical (clone) kepulation Vo = 0, because they clone originated frome single pure line of Vp = v= 10 (de verse than a centrele de Therefore envikommentel variareella) - Vp. In the original Population phenotypic variation Vp - 30 So, the original konulation - 30-10-20 4² - Va - 20 = 0.666 Answer Here v Ve 30 Tere Valve ducrease because Up = Vat Ve will increases