UYU TUTI9W Calc3 Section 14.2: Problem 2 Previous Problem Problem List Next Problem (1 point) Suppose...
6AHW7: Problem 5 Prev Up Next (1 pt) Suppose R is the shaded region in the figure, and f(x,y) is a continuous function on R. Find the limits of integration for the following iterated integrals. Bp D -» [f(3, 3)dA = SL" $12, 9) dy de x,y) dA= f(x,y) dy dx ЈА Јc so || 13 wyda= [." 15:19) de dry We were unable to transcribe this image
Suppose R is the shaded region in the figure, and f(x,y) is a continuous function on R. Find the limits of integration for the following iterated integrals. BD (a) [f $12,9)da = S, "Lº f12, y) dy de PH dA= JE JG f(x,y) dc dy I
Suppose R is the shaded region in the figure, and f(x, y) is a continuous function on R. Find the limits of integration for the following iterated integrals.
Section 16.1 Integration in T Previous Problem Problem List Next Problem (1 point) Evaluate the integral over the rectangle R = [0,7] x [0, 9]. Il 4:+5y dA = JJR Preview My Answers Submit Answers You have attempted this problem 0 times. You have 10 attempts remaining.
I need both of them please. Please solve both of them. THANK YOU. (1 point) Suppose R is the shaded region in the figure. As an iterated integral in polar coordinates, CBD f(x,y)dA = (*%" scrcos(®), r sin@) r dr de JA Jc with limits of integration 1. (Click on graph to enlarge) (1 point) Match each double integral in polar with the graph of the region of integration. 3x/4 -X/2 3x/4 2: 1.6" ["s(,0) r dr de ? -...
Assignment 7: Problem 9 Previous Next Problem List (1 point) Sketch the region of integration and evaluate by changing to polar coordinates: 12 rf) 1 y dx V +y J6 For f(x) = V12x- Answer: 6sgrt3-2p Submit Answers Preview My Answers You have attempted this problem 3 times. Your overall recorded score is 0%6. You have 2 attempts remaining. Email Instructor Assignment 6: Problem 9 Problem List Next Previous (1 point) Set up a double integral in rectangular coordinates for...
6. (4 pts) Consider the double integral∫R(x2+y)dA=∫10∫y−y(x2+y)dxdy+∫√21∫√2−y2−√2−y2(x2+y)dxdy.(a) Sketch the region of integration R in Figure 3.(b) By completing the limits and integrand, set up (without evaluating) the integral in polar coordinates.∫R(x2+y)dA=∫∫drdθ.7. (5 pts) By completing the limits and integrand, set up (without evaluating) an iterated inte-gral which represents the volume of the ice cream cone bounded by the cone z=√x2+y2andthe hemisphere z=√8−x2−y2using(a) Cartesian coordinates.volume =∫∫∫dz dxdy.(b) polar coordinates.volume =∫∫drdθ. -1 -2 FIGURE 3. Figure for Problem 6. 6. (4 pts)...
Ch 5 Sec 3: Problem 10 Previous Problem Problem List Next Problem 1 point) Suppose the region on the left in the figure (with blue shading) has area is 33, and the region on the right (with green shading) has area 3. Using the graph of f(x) in the figure, find the following integrals. f(x) dx = I swds = I code = [ Valdr = Graph of y = f(x) Note: You can earn partial credit on this problem....
1 -1 O 1 2 x FIGURE 3. Figure for Problem 6. 6. (4 pts) Consider the double integral 2 Spa (22 + y)da = [ L. (x2 + y) dx dy + √2-y² (x2 + y) dx dy. (a) Sketch the region of integration R in Figure 3. (b) By completing the limits and integrand, set up (without evaluating) the integral in polar coordinates. Sep (+2 +y)dA = dr do.
6. (4 pts) Consider the double integral∫R(x2+y)dA=∫10∫y−y(x2+y)dxdy+∫√21∫√2−y2−√2−y2(x2+y)dxdy.(a) Sketch the region of integrationRin Figure 3.(b) By completing the limits and integrand, set up (without evaluating) the integral in polar coordinates. -1 -2 FIGURE 3. Figure for Problem 6. 6. (4 pts) Consider the double integral V2 /2-y² + = (x2 + y) dx dy + + y) do dy. 2-y2 (a) Sketch the region of integration R in Figure 3. (b) By completing the limits and integrand, set up (without evaluating)...