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1. Locate the center of gravity of the homogeneous rod bent in the form of a semicircular arc. The rod has a weight per unit
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Answer #1

ğ = 5 simo ..- ñ = 5 cosa ; a=sñ de SAL Tol 5 Coso x5 do le 5 do x= 25 [sino] / H= 5 [1 - (-1)] : 10 Are length = ar = 5* Wagthumbs up thank you!!!

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