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Question 4 0.66/2 View Policies Show Attempt History Current Attempt in Progress - Your answer is partially correct. Impact o
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Answer #1

Solution:

Given: p = 0.75

Sample sizes : n = 30,n = 200 , n = 1100

We have to find standard error for these sample sizes.

Formula:
\sigma_{\hat{p}}= \sqrt{\frac{p \times (1-p)}{n}}

Standard error for n = 30 is:

\sigma_{\hat{p}}= \sqrt{\frac{0.75 \times (1-0.75)}{30 }}

\sigma_{\hat{p}}= \sqrt{\frac{0.75 \times 0.25 }{30 }}

\sigma_{\hat{p}}= \sqrt{ 0 .00625 }

\sigma_{\hat{p}}= 0.079

Standard error for n = 200 is:

\sigma_{\hat{p}}= \sqrt{\frac{0.75 \times (1-0.75)}{20 0 }}

\sigma_{\hat{p}}= \sqrt{\frac{0.75 \times 0.25 }{20 0 }}

\sigma_{\hat{p}}= \sqrt{ 0.0009375 }

\sigma_{\hat{p}}= 0.031

Standard error for n = 1100 is:

\sigma_{\hat{p}}= \sqrt{\frac{0.75 \times (1-0.75)}{11 0 0 }}

\sigma_{\hat{p}}= \sqrt{\frac{0.75 \times 0.25 }{1100 }}

\sigma_{\hat{p}}= \sqrt{ 0.000170455 }

\sigma_{\hat{p}}= 0.013

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