Solution :
This is one tailed test .
The null and alternative hypothesis is ,
H0 :
= 1
Ha :
> 1
Test statistic (t)
= ( -
) / s /
n
= (1.46 - 1) /0.28 / 12
Test statistic = 5.691
P(z > 5.691) = 1 - P(z < 5.691) = 1 - 1
P-value = 0
= 0.05
P-value <
Yes. Reject the null hypothesis .
use data from q7 to answer 11 QUESTION 7 3 points Problem 7 . an environmentalist...
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2) Think of an example with 30 data points
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Purpose
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List of raw data pairs
Frequency distribution (table)
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