Question

a man applies a force perpendicular to the handle of his pressure washer determine the magnitude of the force that the man must exert on the handle

6. A man applies a force P perpendicular to the handle of the high-pressure washer as shown Determine the magnitude P of the force that the man must exert on the handle of the high-pressure washer in order to cause loss of contact at the front support B. The washer has a mass of 60 kg that can be centered at point G. Treat this problem as two-dimensional. (Note: the man prevents the back wheel from moving with his left foot.) 800 mm 310 125

Answer 1

m = 60 kg, W = mg for washer to loss contact at point B, net torque about point '0' must be zero, i.e., sigma M_0 = 0 implies p(800) - W(125) + R_B (310 + 125) = 0. When washer is about to loss contact at 'B', R_B = 0. So, p = 60 times 9.81 times 125/800 implies P = 91.96875 N.