Question

wuestion 01/20 Marks The vendita a ty and the price at the where relation when 2 A , what is the I (5 km/whereth theme of the n dia sention of the partie hectory tract with constant d ong the path that for a short distantes tromos rec ome the sandy ortoit vnity at instant on the cure Aybladet The Scenes pinned at and as a result of the constant prote dhes the peg For a short distance along the spiral guid =(04m where s t in dan Component of the locity and al But the adult the instanta the same as an 2/3 determine the acceleration Brad when ratsat repomponents of the elect The inspired a nd a mult of the total vity 0-3 rad/skrives the per for a short distance along the spiral guider (040) Determine the velocity and acceleration of the particle at the instant l es thesis Ahol meg want acting ang them with power Carmine the way to the in the who le Cene sedan den f or 15 -100 e then ther e then there 35 mish bulalo ad d or the Wading pool 0.7 ms. De hec velit c law. plus P7

please give anwers ?

Answer 1

Soll.ca:: V = (16+29 +4+39 +(St+2) Â 2 m/s ia= dy dt - Cát + Lee -C-120k) dt = (2+ + 12+øj + SÊ m/s2 At t= 2 sec. a =(32x2) 1 + 12+(2) + Sk = (64) + 489 +SR) m/s2 lal = |(64)2+(4892 +(572 180.1561 m/s2 s = ptcicekî + 4t8j+657 +2]) = (lent +"+***+2478) = 150.02329 + 4234 + (5123+2x2] = (42.6677 + 169 +682 m x = 42.667 m y = 16 m 2 = 14m

Chi s'yae sincer) home I CSENJE :: VY STE CVX (caste) v8 = ng tu? *W[i*(Eupaten) ] ** The eage carte) Ny = VETEC cos (EX) CC? Along hosizontal axis (Vo cos@ulti = (vocose) tz Along veretical direction, (vo sin est, Igt. = (vo finen) to fgte .: (Vo sine, ) ti fvo sineste ag(ti-t3) Vo ( Sünorta - Ginésta) = q (uitto] (to -ta)

.. ti = to cos 02 COSA I Now, t-t2 = gvo (sina ti-Só os tz). titt) Bubstitute to in above eq? , we get = Vo sin@-es) Ccos o2 +coso,) ع (ه .3 ا au m = dvſ subliments de + 48*62 (x = sabe le-am = . Surabe 1x = Jam bulan ya da

S। । २१७६ (१)(१०.us) = ०६१ = () १५-= (६-३-२) १-4s - x(x - 2) === = + h4

(d) InB = tex 3 (0,4+0,4) x (0.4+0,4) = 0128 kg. m? Joc = x 3 x15x1.51= 3.375 kgima 12 = [4 cm(pap)larelé+ (mapach) x d2] * * 12 47 (0.34 10.92+ 12 x1 (23)*x (15+0.3727 = 11,095 kg.m2 Those - Europ Aut) x tonda + Compe An) x 42] X 12 XT(0,1)2x10.13 +12XTT ,122 (1.5 +0,337 = 1.223 kgim? - 1.223 Io = IAB +Ioc +Ic-I Hole = 0,128 + 3.375 +11.095 -1.223 =| 13.375 kg. m2 |

(C) EMA = (MK JA NBXL - 60X9.81x0.6 - 40 x 9681 X 0,4 = -60x3 x 1.25-40x3 x 0,4 No - 353.16 – 156,96 = -225-48 .:|MB = 237.12 N | SF y = mcauly MA + Mo -60x9.81 - 40X9.81 = 0 . MA = 743,88 N ]