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Question 1 (1 point) Saved Which identifier name below is illegal in C? |_10C 10C C10 All of them is legalQuestion 2 (1 point) You have the declaration as below int a = 0; Which line below will give you a warning when compiling? prQuestion 3 (1 point) Which line below is equivalent to System.out.println(Hello World”); in Java? printf(Hello World\n); pQuestion 4 (1 point) Suppose we have the code below int a= 1, b = 0; double c = 2.1, d = 3.3; a = c + d; printf(%d, a); WhaQuestion 5 (1 point) Suppose we have the code below int a= 1, b = 0; double c = 2.1, d = 3.3; a = c + d; printf(%f, a); Wha

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Answer #1

1) 10C

Identifiers are nothing but names of variables,functions,arrays,structure etc.The first character of an indetifier should be either alphabet or underscore.It should not begin with any numerical digit.Hence 10C is illegal identifier since it begins with number while other two identifiers begin with alphabet and underscore.

2)printf("%f",a);

Above option will thrown a warning since it expects argument of type 'double' but a is of type int.

printf("%x",a) this will output lowercase hexadecimal number without any warnings

printf("%o",a) this will output octal number without any warnings

3)printf("Hello World\n");

System.out.println("Hello World") prints Hello World in a new line , we can achieve similar output by using '\n' in printf.

4)output : 5

a is declared as int so after adding c and d result is 5.4 which will be stored in int data type i.e. 5

Hence printf("%d",a) will format a in int and print 5

5)output : A meaningless number

since printf("%f",a) expects argument of type double and a is of type int.The compiler do not automatically cast your int to float

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