Question

VERY IMPORTANT

A current path shaped as shown in Figure produces a magnetic field at the center of the arc. If the arc subtends an angle of 0-27 degree and the radius of the arc is 0.2 m, what is the magnetic field vector (nt) if the current is 6 A7 Provide your answer with one decimal place. xy, and z directions are shown in the figure. Take Po - 410-Tm/A De Р

Answer 1

Blution You field due to an e of must know, magnetic i at its center is angle Mo I love) 360 B = Mo I 2R R = Relies of Direction of B is given as, arc whore I I R d P P (B into the paper) (B out of the paper)

X10%? T Hence for our case ase, BC subtend O = 87' , I- 6A Que ... 13 z I and Redius R = 0.2m pvo R С. I magnitude of magnetic field at P, 3= Mo I QR o 360 09T B = 412X10-7 x 6 ( 27 360 ) = 1413 x 10 2x 0.2 13 = 1413 B = or 1413 nT and direction is into the paper z .: B = -(1413 nt) 2 Magnetic field vector >

Hope you like my solution & my efforts in Note: - The segments AB and cp does not contribute any magnetic field at point a because point p is on the une containing these two straight segments & when this happen, no contribution from straight Segments accur .