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A student begins with 10.2 mL of a 0.28 M Cu(NO_3)
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Answer #1

mass of Cu -> mol of Cu -> MV

mol of Cu = MV = 10.2*0.28 = 2.856 mmol of Cu

mass = mol*MW = (2.856*10^-3)(63.5)= 0.181356 g of Cu

theoretical yield --> 0.181356 g

actual yield -->0.079 g

% yield = real/theoretical * 100% = 0.079 0.181356*100 = 43.560%

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A student begins with 10.2 mL of a 0.28 M Cu(NO_3)_2 solution and performs copper cycle...
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