Calculate the expected E value for the cell in which E0= 1.100 V, F=96,500 J/V R=8.31 T=25 0degrees celcius. Zn+Cu2+ (.25M) ----> Zn2+ (.5M) +Cu
What is Delta G?
Calculate the expected E value for the cell in which E0= 1.100 V, F=96,500 J/V R=8.31...
Constants The following values may be useful when solving this tutorial. Constant Value E∘Cu 0.337 V E∘Zn -0.763 V R 8.314 J⋅mol−1⋅K−1 F 96,485 C/mol T 298 K Part A Part complete In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. The two half-reactions that occur in the...
8. The standard cell potential (E°cell) for the reaction below is +1.10 V. Calculate the cell potential for this reaction when the concentration of [Cu2+] = 1.0 × 10-5 M and [Zn2+] = 3.5 M. Zn (s) + Cu2+ (aq) → Cu (s) + Zn2+ (aq)
The cell Cu(s)(1M) | Cu2+ || (1M) | Cu(s) has E = 0.182 V The cell Pt(s) | Cu+(1M) | Cu2+ || Cu+ | (1M) | Cu(s) has E = 0.364 V How do you calculate delta G?
Calculate E for the following electrochemical cell at 25°C Cu|Cu2+(0.01M) || Zn2+(0.05M)]Zn Select one: a. -0.977V cb. -1.598V c. -1.080V d. -1.122V ce. -1.311V
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
1) Calculate the cell potential, E°cell, for the following electrochemical reaction. Cu(s) + I2(g) → Cu+2(aq) + 2I-1(aq) E = ? a.-0.87 V b.-0.19 V c.0.19 V d.0.87 V 2) Calculate the equilibrium constant (Keq) for the following reaction at 25 °C? (Faraday's Constant = 96,500 J / V · mol) & (R = 8.314 J / mol · K) 2Fe+3(aq) + Sn+2(aq) → 2Fe+2(aq) + Sn+4(aq) K = ? a. 4.04 x 107 b. 3.44 x 1018 c. 4.48...
se the tabulated half-cell potentials to calculate ??-for the following ,edo-m-mm in (7 points ) Tabulated half-cell potentials (Reduction) Zar" (aq) + 2 e-? Zn(s) E.--0763 V Cl:(g) +2e2 CT(a)+1.358 F-96,485 C/mol. electron, 13-1 C.V and 1kJ -1000 C). (7 points) 4) Calculate K for the oxidation of copper by H' (at 25 Cu(s) + 2 r(aq) ? Cu2+(aq) + H2(g) Tabulated half-cell potentials (Reduction) Cu2 (aq) + 2 e-Al(s) E-0.34 v 2H+(aq) + 2 e--+ H2 (g) E#20.00 V...
Calculate the E°cell for the following reaction: Cu2+ (aq) + Ni (s) → Cu (s) + Ni2+ (aq) A) (-0.59 ± 0.01) V B) (-0.09 ± 0.01) V C) (0.59 ± 0.01) V D) (0.09 ± 0.01) V --------------------------------------------------------------------------------------------------------- What is the proper line notation for the following reaction? Cu (s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag (s) A) Cu2+ | Cu || Ag | Ag+ B) Ag+ | Ag || Cu | Cu2+ C) Cu |...
Using the information in the table: Which combination of metals, if used to create an electrochemical cell, would produce the largest voltage? Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e + Cu2+(aq) + 2e → Cu(s) Zn(s) + Cu2+ (aq) → Zn2+ (aq) + Cu(s) E half-cell = 0.7628 V Eºhalf-cell =...
Using the table below: 19. Three combinations of metals are listed below, which combination would produce the largest voltage if they were used to construct an electrochemical cell? Copper (Cu) with zinc (Zn) Lead (Pb) with zinc (Zn) Lead (Pb) with cadmium (Cd) Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e +...