Calculate E for the following electrochemical cell at 25°C Cu|Cu2+(0.01M) || Zn2+(0.05M)]Zn Select one: a. -0.977V...
In an electrochemical cell composed of Zn(s)|Zn2+|| Cu2+, Cu(s), Which species is the oxidizing agent? Which species is the reducing agent? In an electrochemical cell composed of Zn(s)| Zn2+1| Cu2+|Cu(s), Which electrode could be replaced with an inert electrode (such as Pt)? Which species is the anode? Which species is the cathode?
Choose the correct Nernst equation for the cell Zn + Cu2+ à Zn2+ + Cu E = E° - 0.0296 log(Cu / Zn) E=E° - 0.059 log([Zn2+] / [Cu2+]) E = E° - 0.0296 log(Zn / Cu) E = E° - 0.0296 log([Zn2+] / [Cu2+]) E = E° - 0.0296 log([Cu2+] / [Zn2+]) 20 points
What is the potential of a cell made up of Zn/Zn2+ and Cu/Cu2+ half-cells at 25°C if [Zn²+1 -1.00 Mand (Cu2+] = 0.05 M?
What is E for a cell where E°=1.10 (Cu2++Zn→Cu+Zn2+), [Cu2+]=1.25 M, and [Zn2+]=0.0075 M at SATP? 1.25 V 0.95 V 1.03 V 1.17 V
Given: Zn2+ (aq) + 2e Zn(s); E--0.76 V Cu²+ (aq) +20 Cu(s); E° -0.34 V What is the cell potential of the following electrochemical cell at 25°C? Zn(s) | Zn2+(1.0 M) || Cu2+(0.0010 M) Cu(s) a) greater than 1.10 v b) between 0.76 and 1.10 V c) less than 0.42 V d) between 0.00 and 0.76 V e) between 0.34 and 0.76 V
Calculate for the reaction: Zn! Zn2+ (0.60M)| |Cu2+ (0.20M)|Cu Given the following: Cu2+(aq) + Zn(s) Cu(s) + Zn2+(aq) Eo-1.10V
Consider an electrochemical cell with the following cell reaction; Zn(s)+ Cu (aq) Zn2 (aq)+ Cu(s) where [Cu+2] 0.01, [Zn+9-0.1 M. What will be the e.mf?
2. In this lab, you will use a Zn-Cu electrochemical cell similar to the one shown in Figure 12.1. The overall chemical reaction occurring in this cell is: Zn(s) + Cu2+(ag) → Zn2+(aq) + Cu(s) a. In this reaction, how many electrons are being transferred from one substance to the other? Explain how you can determine this from the reaction shown above. b. Which metal is gaining electrons and which metal is losing electrons? c. Explain the function of a...
The voltage of the cell combination of Cu/Cu2+ and Zn/Zn2+ is 0.953V. The standard reduction potential for Cu/Cu2+ is expected to be 0.34V. Determine the reduction potential for Zn/Zn2+
What is E for a cell where Eº=1.10 (Cu2++Zn--Cu+Zn2+), [Cu2+3=1.50 M, and [Zn2+2=0.0050 M at SATP? 0.93 V 1.27 V 1.17 V 1.03 V