Question

Choose the correct Nernst equation for the cell Zn + Cu2+ à Zn2+ + Cu E = E° - 0.0296 log(Cu / Zn) E=E° - 0.059 log([Zn2+] / [Cu2+]) E = E° - 0.0296 log(Zn / Cu) E = E° - 0.0296 log([Zn2+] / [Cu2+]) E = E° - 0.0296 log([Cu2+] / [Zn2+]) 20 points

Answer 1

the given overall reaction is
Zn + Cu2+ --> Zn2+ + Cu

nernst equation E = E0 -0.0592/n logQ

where Q= reaction quotient , which is given by concentration of products/concentration of reactants
Since concentrations of solid it taken as 1

Q = [zn2+]/[Cu2+]

and n= 2 ;since 2 electrons are involved in the overall reaction

Thus Ecell = E0 - 0.0296 log{[Cu2+]/[Zn2+]}

is the answer
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