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+ ColFun Phys1 24.P.032. Find the image distance and linear magnification for a small object on the optical axis, 20.2 cm fro

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Answer #1

1/v = (1/f) + (1/)

= {1 ÷(- 20.2)} + {1÷(- 10)}

= - 0.1495

v = 1 ÷ ( -0.1495)

= - 6.69 cm

Image distance = 6.69 cm

Linear magnification

m = v/u = (- 6.69) ÷ ( -20.2) = 0.33

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