Question

A hockey stick is in contact with a 165-g puck for22.4 ms; during this time, the force on the puck is given approximately by F(t)=a+bt+ct2,where  a = −25.0 N, b = 1.13 × 105 N/s, andc = −5.58 × 106 N/s2.

A) Determine the speed of the puck after it leaves the stick.

B) Determine how far the puck travels while its in contact with the stick.

Answer 1

According to newton second law, dv dt (a+bt + ct2)-mav Integrate on both sides, (-25 N) (22.4x103 s+(1.13x105 N/s +(-5.58x10 Ns 22410 s 0.165 kg 41.72 m/s The velocity formula is, ds dt Substitute v in above equation. 2 3ds dt Integrate on both sides, (-25 N) 22.410 5+(1.13x101 Ns) 22.4x10-3s H(-5.58x105 N/s)(22.4x10 s) 0.165 kg -0.4 m