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12. Use Hess's Law to find AH for this reaction. (5) NO2(g) +2H2(g) ---> 2H2O(e) +...
Hess's Law Practice Find AH° for the following equation: SiO2(s) + 4HF(g) → SiF4(g) + 2H2O(g) Using the following equations: Si(s) + O2(g) → SiO2(s) Si(s) + 2F2(g) → SiF4(g) H2(g) + F2(g) → 2HF(g) H2(g) + 4202(g) → H2O(g) AH = -910.9 kJ/mol rxn AH = -1651 kJ/mol rxn AH = -542 kJ/mol rxn AH = -241.8 kJ/mol rxn
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
Please explain step by step 12. Calculate the standard reaction enthalpy for the reaction: N2H4(4) + H2(g) → 2NH3(g) Given: N2H4(4) + O2(g) → N2(g) + 2H2O(g) AH° = 0543 kJ 2H2(g) + O2(g) → 2H2O(g) AH° = 1484 kJ N2(g) + 3H2(g) + 2NH3(g) AH° = 092.2 kJ A. - 1119 kJ B. - 33 kJ C. -151 kJ D. + 151 kJ E. + 1119 kJ
Determine AH for the following reaction, 2NH3(g) + 5/20260) - 2NO(g) + 3H2019) given the thermochemical equations below. N2(g) + O2(0) - 2NO(g) N2(g) + 3H2(g) — 2NH3(0) 2H269) + O26) - 2H206) AH = +180.8 kJ AH = -91.8 kJ AH = -483.6 kJ -1178.2 kJ -452.8 kJ -394.6 kJ -211.0 kJ +1178.2 kJ
Hess's Law Given the following data: P(s) + 3/2H2(g) → PH3(g) ΔH°= +5.0 kJ PH3(g) + 2O2(g) → H3PO4(l) ΔH°= -1272.0 kJ 2P(s) + 5/2O2(g) → P2O5(s) ΔH°= -1492.0 kJ H2(g) + 1/2O2(g) → H2O(l) ΔH°= -286.0 kJ calculate ΔH° for the reaction: H3PO4(l) → 1/2P2O5(s) + 3/2H2O(l) ΔH°=?? also please explain how you found the answer
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
Use Hess's law and the following data CH4(g) + 2O2(g) → CO2(g) + 2 H2O(g) AH° = -802 kJ mol-1 CH4(8) + CO2(g) —> 2CO(g) + 2 H2(g) AFH° = +247 kJ mol-1 CH4(g) + H2O(g) –> CO(g) + 3H2(g) AFH° = +206 kJ mol-1 to determine A.Hº for the following reaction, an important source of hydrogen gas CH4(8) + +02(8) — CO(g) + 2 H2(8)
DaC. NUL20 1) Find AH, for the reaction 2H2(g) + 2C(s) + O2(g) → C2H5OH(I), using the following thermochemical data. For Hess's Law, rewrite equations to find out AH. C2H5OH (1) +2 02 (g) → 2 CO2 (g) + 3H20 (1) AH = -875.J C(s) + O2(g) → CO2 (g) AH = -394,51 kJ H2(g) + 12 02 (g) → H20 (1) AH = -285.8 kJ
AH 20. HESS'S LAW. Calculate the AH for the reaction: IF.) → Fle) + Flel Use the following data: a. IF(g) + Fle) → 1f3(E) AH = -390 kJ b. IF(g) + 2F2(e) → Fle) AH = -745 +1135 - 1135