Lets number the reaction as 0, 1, 2 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 0 = +1 * (reaction 1) -1 * (reaction 2)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = +1 * ΔHo rxn(reaction 1) -1 * ΔHo rxn(reaction 2)
= +1 * (-390.0) -1 * (-745.0)
= 355 KJ
Answer: + 355
AH 20. HESS'S LAW. Calculate the AH for the reaction: IF.) → Fle) + Flel Use...
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
6. Hess's Law. Use the data in Table 1 to calculate AH for the reaction below: Table 1. Change in Enthalpy for Reactions Reactions Change in Enthalpy (AH) AH = -393.5 kJ/mol (1) C() (2) Hz((g) + + O2(g) O2(g) → CO2(8) → H2O(l) AH2 = -285.8 kJ/mol (3) 2CH.(g) + 702(g) → 4 CO2(g)+ 6H2O(1) AH = -283.0 kJ/mol Calculate the enthalpy change for the reaction: 2 C(s) + 3H2(g) → CzH6(g) AH = kJ/mol
12. Use Hess's Law to find AH for this reaction. (5) NO2(g) +2H2(g) ---> 2H2O(e) + NHs(g) Given the following two equations: 2NH3(g) -->N2(g) + 3H2(g) AHo +92 kJ 2N2(g)+ 2H2O(l) ---> NO2(g) + 2H2(g) AH° = +170 kJ
Use the standard reaction enthalpies given below and Hess's Law to determine AH°rxn for the following reaction: Input answer in kJ rounded to the ones place with the correct sign. X4(g) + 10 Y2(g) →4XY5(s) AHørxn = ? Given: XY5(s) → XY3(g) + Y2(g) AHºrxn=-157 kJ X4(g) + 6 Y2(g) →4 XY3(g) AH°rxn = 1,363 kJ
Ho ilacer e trunschpl Use Hess's Law to calculate the standard enthalpy (AHº) for the foll standard enthalpy (AH) for the following reaction inolonce to the on an C(s) + O2(g) → CO(g) given the following two equations. C(s) +502(9) – co(9) AH° = -110.5 kJ CO2(g) – CO(g) +502(9) AH° = +283.0 kJ [15]
- + ~ [ Fit to page 1 11. Hess's Law - Calculate the enthalpy for the following reaction (20 pts) 11.1. NzH4 (1) ► N; (g) + 2H; (g)AH = ? Consider that N2H4 (1) +02 → N(g) + H20 (g), AH = -543.2 kJ 2H2(g) + O2 → H20 (g), AH = -241.8 kJ
Hess's Law Practice Find AH° for the following equation: SiO2(s) + 4HF(g) → SiF4(g) + 2H2O(g) Using the following equations: Si(s) + O2(g) → SiO2(s) Si(s) + 2F2(g) → SiF4(g) H2(g) + F2(g) → 2HF(g) H2(g) + 4202(g) → H2O(g) AH = -910.9 kJ/mol rxn AH = -1651 kJ/mol rxn AH = -542 kJ/mol rxn AH = -241.8 kJ/mol rxn
Question 5 Use the standard reaction enthalpies given below and Hess's Law to determine AH°rxn for the following reaction: Input answer in kJ rounded to the ones place with the correct sign. X4(g) + 10 Y2(g) 4XY5(s) AHºrxn = ? Given: XY5(s) - XY3(g) + Y2(g) AHºrxn= -157 kJ X4(g) + 6 Y2(g) + 4 XY3(g) AHºrxn = 1,146 kJ
Help me get the answer -78.5 2) Use Hess's law to calculate the enthalpy of the reaction below using the following information. [Ans: -78.5] HCl(g) + NaNO2(s) → HNO2(1) + NaCl(s) AH=? 2NaCl(s) + H2O(l) + 2HCl(g) + Na2O(s) NO(g) + NO2(g) + Na2O(s) - 2NaNO3(s) NO(g) + NO2(g) N2O(g) + O2(g) 2HNO2(1) - N2O(g) + O2(g) + H2O(1) AH = 507 kJ AH = -427 kJ AH = -43 kJ AH = 34 kJ
Use Hess's Law to calculate the enthalpy change for the reaction WO3 (s) + 3 H2 (g) --> W (s) + 3 H20 (g) AH= ? kJ from the following data: 2 W (s) + 3 O2(g) --> 2 WO3(s) 2 H2(g) + O2(g) --> 2 H20 (g) AH = -1685.4 kJ AH= -477.84 kJ The following program calculates the income tax of a person based on his gross income and the number of dependents in his family, however there...