Question

Assignment O2 Question of Save 14. An available channel for FM transmission is 68 kHz wide. The maximum allowable modulating signal frequency is 3.5Hz. What should be the deviation rato? Round the final awwer to two decimal places Hints References eBook & Resources co 2 $ 4 3 E 5 & 7 6 7 V 8 A 9 0 E R T Y DES U ОР €

Answer 1

CJA deviation ratio = Available Channel Maximum allowable onodillating signal frequency 58 kH3 3.5kHz deviation ratio 16.5714 kHz = 16.57 kH3( sounding off to two decimal places) 24 Given percentage of modulation = 75% Ve=240V Vm=? Percentage 1/2 of modulation = 2 +42 whele M= modulation index M = Vm VC Percentage of modulation - 75% = 0.75 M2 0.75 = Q+ M2 → 1-5 = 0.25 M2 1.5 +0.75 M² M² M² 1.5 0.25 M² - 6 - Vm VC

Vm = 56 Ve -> vm 940 = 56 Vm = 24006 240 [ 2.4493 Um = 587.87 v) Amplitude of modulating signal needed is 587.87 v