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Cd2+(aq) + 2 e-←→ Cd (s) Cu (aq) + eCu (s) Ag+(aq) + e-←→ Ag (s) E=-0.41 V E +0.52 V E +0.80 v 3. Based on the standard elec
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Answer #1

Ans. a. Cd(s)

Explanation: A reducing agent or reducer is an element or compound that lose or donate electrons to other element or compound present in the reaction. A reducing agent is oxidized because it loses electrons in the redox reaction. In Cd2+, 2+ is the highest oxidation state of cadmium. Since Cd2+ is already is in a oxidation state of 2+, it can be further oxidized. So the answer is the metal, Cd.

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