2- The following linear programming problem maximizes the profit in a manufacturing setup. Suppose that the...
S- In the optimal table of the simplex for the following linear programming problem x1, x3, are the basic variables. Min Z=-5X1+3X2+X3 X1+X2-X3<=10 X1+X2+X3<=60 What is the range for the first constraint right hand side for which the optimal table remains feasible? a. b. Is it profitable to increase a unit of resource for the 2nd constraint, if each unit of this resource is purchased for $2? What is the value of objective function and decision variables for this problem?...
Solve the following linear programming problem graphically: Maximize Z=4X₁+4X₂, Subject to: 3X₁ + 5X₂ ≤ 150 X₁ - 2X₂ ≤ 10 5X₁ + 3X₂ ≤ 150 X₁, X₂ ≥ 0 1) Using the line drawing tool, plot the constraints by picking two endpoints for each line. Do not plot the nonnegativity constraints. 2) Using the point drawing tool, plot the five corner points which define the feasible region. The optimal solution is X₁ = _______ and X₂ = _______ (round your responses to two decimal places). Maximum profit is $_______
Problem #5 -- Consider the following linear programming problem: Maximize Z = 2x1 + 4x2 + 3x3 subject to: X1 + 3x2 + 2x3 S 30 best to X1 + x2 + x3 S 24 3x1 + 5x2 + 3x3 5 60 and X120, X220, X3 2 0. You are given the information that x > 0, X2 = 0, and x3 >O in the optimal solution. Using the given information and the theory of the simplex method, analyze the...
1. Solving the linear programming problem Maximize z 3r1 2r2 3, subject to the constraints using the simplex algorithm gave the final tableau T4 T5 #210 1-1/4 3/8-1/812 0 0 23/4 3/8 7/8 10 (a) (3 points) Add the constraint -221 to the final tableau and use the dual simplex algorithm to find a new optimal solution. (b) (3 points) After adding the constraint of Part (a), what happens to the optimal solution if we add the fourth constraint 2+...
5. Suppose that (x1, X2, X3) is a feasible solution to the linear programming problem 4r, +2x2 + x3 minimize X12 3, 2a 23 2 4, subject to Let y and ybe non-negative numbers (a) Show that x1(y2y2)2(-y12) + x3y2 2 3y14y2 1 (b) Find constraints on yi and y2 so that 4x12 2 x1(y1 + 2¥2) + x2(-y1 + Y2) + x3Y2 1 at every feasible solution (xi, x2, X3) (c) Use parts (a) and (b) to find a...
Find the complete optimal solution to this linear programming problem (using Excel) and enter the optimal x value. Max 5X + 6Y s.t. 3X + Y <= 15 X + 2Y <= 12 3X + 2Y <= 24 X , Y >= 0 Find the complete optimal solution to this linear programming problem using Excel and type in the optimal value of X below (X*=?). Max 2X + 3Y s.t. 4X + 9Y <= 72 10X + 11Y <= 110...
Consider the following linear programming problem. Maximize p = 5x + 7y subject to the constraints 3x + 8y ≤ 1 4x - 5y ≤ 4 2x + 7y ≤ 6 x ≥ 0, y ≥ 0 Write the initial simplex tableau.
The following linear programming problem has been solved by LINDO. Use the output to answer the questions. (Scroll down to see all). LINEAR PROGRAMMING PROBLEM MAX 41X1+52X2+21X3 S.T. C.1) 5X1 + 5X2 + 9X3 < 1200 C.2) 11X1 + 14X2 + 5X3 < 1500 END LP OPTIMUM FOUND AT STEP 1 OBJECTIVE FUNCTION VALUE 1) 5795.049 VARIABLE VALUE REDUCED COST X1 0.000 0.217822 X2 74.247 0.000000 X3 92.079 0.000000 ROW SLACK OR SURPLUS DUAL...
SOLVE STEP BY STEP!
4. Consider the following LP: Minimize z = x; +3x2 - X3 Subject to x + x2 + x2 > 3 -x + 2xz > 2 -x + 3x2 + x3 34 X1 X2,43 20 (a) Using the two-phase method, find the optimal solution to the primal problem above. (b) Write directly the dual of the primal problem, without using the method of transformation. (c) Determine the optimal values of the dual variables from the optimal...
[4.37] Consider the following problem: Maximize 2x + 3x2 subject to X1 + 2x2 5 10 -*1 + 2x2 s 6 *1 + *2 S6 12 0. a. c. X1, Solve the problem graphically and verify that the optimal point is a degenerate basic feasible solution. b. Solve the problem by the simplex method. From Part (a), identify the constraint that causes degeneracy and resolve the problem after deleting this constraint. Note that degeneracy disappears and the same optimal solution...