![1.2DE-02 1 10E-02 1.00E-02 9.008-03 8 ODE-03 7.ODE-03 6.0CE-03 5.00E-03 .00E-03 Rx y-0.00142x+0.00006 60 12 Voltage [V] Fig. 1 Fig. 2 When verifying Ohms law, you plotted a current-voltage graph based on the measured data for an unknown resistor, as shown in Fig. 2. Its resistance is estimated to be 9.](http://img.homeworklib.com/questions/39ca91b0-7c46-11eb-933a-3b39a9936936.png?x-oss-process=image/resize,w_560)
Homework Answers
If I-V GRAPH is straight line then resistance is ohmic and reciprocal of slope gives value of resistance.
y=mx + c here m (slope) is .00142 so
Resistance is 1/m =1/.00142= 704 ohm
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when verifying ohm’s law, you plotted a current-voltage graph based
on the measurements data for unknown...
When verifying Ohm's law, you plotted a current-voltage graph based on the measured data for an unknown resistor
When verifying Ohm's law, you plotted a current-voltage graph based on the measured data for an unknown resistor, as shown in Fig. 2. Its resistance is estimated to be a. 0.00006 Ω b. 0.00142Ω c.16.7kΩ d, 704 Ω
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The voltage drop (V) across a resister is proportional to the current (I) through the resister. Ohm's Law: V = IR. Wednesday's laboratory expernnent attempts to verify Ohm's Law and measure the resistance (R) of a resister Ammeters and voltmeters potentially have offsets, resulting in a constant added to the equation: V = IR + VO If voltage satisfying this equation is plotted against current, the result is a line. With voltage on the y-axis and current on the r-axis,...
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