Question

Name: When drawing Lewis structural diagrams, be sure to explicitly showstosbe electron pairs, unpaired electrons, and formal charges 1) (15 points) Draw the full Lewis structure of 1, along with two other siccant resonance foems Show arrow-pushing necessary to convert 1 to 2 and 2 to 3. po 1 (tull Lewis structure) Which of the three structures is/are the main resonance contributors Briels espais 2) (10 points) Write both full and condensed electron configurations of the following elements full (i.e. 15...) condensed (ie. Hel) a) Li b) C c)s d) Br

Answer 1

H IO དང་ ༦༠ cH， , པ་དང་། བས་བ ་ s )-cA3 Hzcz་ ScNCH, ག་ ལས་ དང་ ག་ཅི་ཡང་ , Á Học Hac= CH3 CH3 CH3

There are some rules to predict main resonance contributor in the resonance structures,

• If in a resonance structure all atoms are complete octet then it is considered as major contributor
• If it has the least number of formal charges then it is considered as major contributor
• If the negative formal charge on the highest electronegative atom and positive formal charge on least electronegative atom then it more stable and lower in energy, hence it is the main resonance contributor
• It is also having more number of covalent bonds then it is considered as major contributor

based on above rules Structure 3 is the main resonance contributor, it is due to in structure 3 every atom is full octet and having more number of covalent bonds.

2)

1. Li atomic number is 3 hence it accommodate with three electrons in its shell

             Full electron configuration = 1s²2s¹

             Condensed electron configuration = [He]2s¹

2. C atomic number is 6 hence it accommodate with 6 electrons in its shell

             Full electron configuration = 1s²2s²2p²

             Condensed electron configuration = [He] 2s²2p²

3. S atomic number is 16 hence it accommodate with 16 electrons in its shell

             Full electron configuration = 1s²2s²2p⁶3s²3p⁴

Condensed electron configuration = [Ne] 3s²3p⁴

4. Br atomic number is 35 hence it accommodate with 35 electrons in its shell

             Full electron configuration = 1s²2s²2p⁶3s²3p⁶3p⁶3d¹⁰ 4s²4p⁵

Condensed electron configuration = [Ar] 3d¹⁰ 4s²4p⁵