From the given information,
The required answers are,
a. P(X=3)=0.7193
b. P(X=0)=0.0011
c. P(X>2)=0.9698
d. Mean=2.6680
Sd=0.5287
On average, 2.6680 orders correctly filled, while there is an approximate variation of 0.5287 from average number of orders 3.
Thank you.
we use those 2informations to do the following questions 0 Restaurant Data Probability of Correct Order...
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