Question

Can humans choose a number randomly? Fifty adults were asked to chose a random number from...

Can humans choose a number randomly? Fifty adults were asked to chose a random number from one to eight. Use α = 0.05 as the level of significance. The table below summarizes the results.
Number 1 2 3 4 5 6 7 8 Frequency 5 3 10 13 7 2 4 6

(a) Calculate the degrees of freedom

(b)Calculate the test statistic x^2

(c)If the critical value is χ2 0.05 =14.067 should you accept or reject the null hypothesis?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

(a) Calculate the degrees of freedom

As n = 8

the df = n - 1 = 8 - 1 = 7

df = 7

(b)Calculate the test statistic x^2

Event Observed Frequency(O) Expected Probability Expected Frequency ( E) ( O-E)^2 ( O-E)^2/E
1 5 0.125 6.25 1.5625 0.25
2 3 0.125 6.25 10.5625 1.69
3 10 0.125 6.25 14.0625 2.25
4 13 0.125 6.25 45.5625 7.29
5 7 0.125 6.25 0.5625 0.09
6 2 0.125 6.25 18.0625 2.89
7 4 0.125 6.25 5.0625 0.81
8 6 0.125 6.25 0.0625 0.01
Sum 50 1 50 - 15.28

\chi^2 = 15.28

(c)If the critical value is χ2 0.05 =14.067 should you accept or reject the null hypothesis?

Null hypothesis: The probability are equal

Alternate hypothesis: At least one probability is different

We reject the null hypothesis

If \chi^2 > χ2 0.05 ( 15.28 > 14.067 )

hence the null hypothesis is rejected

Add a comment
Know the answer?
Add Answer to:
Can humans choose a number randomly? Fifty adults were asked to chose a random number from...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (1 point) A sample of 6 measurments, randomly selected from a normally distributed population, resulted in...

    (1 point) A sample of 6 measurments, randomly selected from a normally distributed population, resulted in a sample mean, t = 7.7 and sample standard deviation s = 1.2. Using a = 0.05, test the null hypothesis that the mean of the population is 7.2 against the alternative hypothesis that the mean of the population, j < 7.2 by giving the following: (a) the degree of freedom (b) the critical t value (c) the test statistic The final conclustion is...

  • Randomly selected students in a statistics class were asked to report the number of hours they...

    Randomly selected students in a statistics class were asked to report the number of hours they slept on weeknights and on weekends. At α = 0.05, the experimenter wants to know if there is sufficient evidence that there is a difference in the mean number of hours slept. Student                 1          2          3          4          5          6          7          8 Hours Sun-Thurs           8          5.5       7.5       8          7          6          6          8 Hours                                 Fri-Sat                  4          7          10.5     12        11        9          6          9 a.   State the hypotheses and identify the claim. b.   A student calculates the test statistic using this formula: Is this the correct formula to use for this situation? (Hint:...

  • Sixty-four students in an introductory college economics class were asked how many credits they had earned...

    Sixty-four students in an introductory college economics class were asked how many credits they had earned in college, and how certain they were about their choice of major. At α = .02, is the degree of certainty independent of credits earned? Credits Earned Very Uncertain Somewhat Certain Very Certain Row Total 0 – 9 15 7 2 24 10 – 59 10 5 6 21 60 or more 4 10 14 28 Col Total 29 22 22 73 Click here...

  • Fifty randomly selected car salespersons were asked the number of cars they generally sell in one...

    Fifty randomly selected car salespersons were asked the number of cars they generally sell in one week. Nine people answered that they generally sell three cars; twelve generally sell four cars; fourteen generally sell five cars; five generally sell six cars; ten generally sell seven cars. Complete the table. Data Value (# cars) data value (# cars) frequency relative frequency cumulative relative frequency 3 4 5 6 7

  • On hundred and fifty-one (151) De Anza College students were surveyed and asked two questions: (1)...

    On hundred and fifty-one (151) De Anza College students were surveyed and asked two questions: (1) How many units are you taking this quarter, and (2) How many hours of television do you watch per day. The chart below summarizes the data. We wish to conduct a hypothesis test to determine if the number of units a student takes is independent of the number of hours per day of television the student watches. Number of units Hours of T.V. per...

  • It has been suggusted that the highest priority of retirees is travel. Thus, a study was conducted to investigate the differences in the length of stay of a trip for pre- and post-retirees. A sample o...

    It has been suggusted that the highest priority of retirees is travel. Thus, a study was conducted to investigate the differences in the length of stay of a trip for pre- and post-retirees. A sample of 700 travelers were asked how long they stayed on a typical trip. The observed results of the study are found below. Number of Nights Pre-retirement Post-retirement Total 4−7 238 172 410 8−13 84 62 146 14−21 33 58 91 22 or more 17 36...

  • It has been suggusted that the highest priority of retirees is travel. Thus, a study was...

    It has been suggusted that the highest priority of retirees is travel. Thus, a study was conducted to investigate the differences in the length of stay of a trip for pre- and post-retirees. A sample of 689689 travelers were asked how long they stayed on a typical trip. The observed results of the study are found below. Number of Nights Pre-retirement Post-retirement Total 4−74−7 238238 163163 401401 8−138−13 7979 6363 142142 14−2114−21 3333 5656 8989 2222 or more 1717 4040...

  • A random sample of 792 subjects was asked to identify the day of the week that...

    A random sample of 792 subjects was asked to identify the day of the week that is best for quality family time. Consider the claim that the days of the week are selected with a uniform distribution so that all days have the same chance of being selected. The table below shows goodness-of-fit test results from the claim and data from the study. Test that claim using either the critical value method or the P-value method with an assumed significance...

  • Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel....

    Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1 = 4, s1 = .20, n1 = 15, x⎯⎯2 = 4.25, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...

  • Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel....

    Do a two-sample test for equality of means assuming unequal variances. Calculate the p-value using Excel. (a-1) Comparison of GPA for randomly chosen college juniors and seniors: x⎯⎯1 = 4, s1 = .20, n1 = 15, x⎯⎯2 = 4.25, s2 = .30, n2 = 15, α = .025, left-tailed test. (Negative values should be indicated by a minus sign. Round down your d.f. answer to the nearest whole number and other answers to 4 decimal places. Do not use "quick"...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT