Question

Using the method of sections, determine the forces in members BC, BH and GH. Make sure to denote whether the members are in tension or compression. lm Z- 6

Answer 1

Page No. Dato # Method of gections B. Using equillibrium equations to determine 3 reartions 11KN 6KN at point A and point E 2KN EFvertcat =0 RA + RE = 19 KN taking moment about poìnt E EME=0 + 6x 3 2x9+11 x6 RAX 12 =0 and (RE =10 5KN ERA =8:5 KN Dracwing section to determine FBC force the angle betueen member BG and is FBH BH FGH GH tane = BG RA EN B = tan' 3) %3D 0=45°

(2 Page No. Date In this problem we consider left section and the right side of the sectson will be igroed for force calculations Hole: Thineथ to be tensile in nature, while solving the equillibrium, all the forres to be determined equations we automatically get the natue of forres ) Taking vertical equillibrium EFy=O FBL FBHSine FBH COSe+ a- RA FBH COSO FGH FBH RA 8.5-2 त्रिट COSC4S) ( FBH =D919 KN3 tensile. assumed direction of H is is tensile in Answer is posrtive FBH conrect nature. 2) Taking moment about point H, since FBH and GH pass thnough H they do not add to moment equation हu्र clockcoise EMH = 0 %3D .. - FBCX3 + 2x3 - RAX6 moment as hegtire momemt -FBCX3 + 6 - 51 FBC =-15 KN answer is ngartive w rong assumed direction of tBL was nature FBL is compressive in

Paga No. (3 Date Fex = ISKN) Compressive. comected direction) of FBC FBC > FBHSino FBH FBH OSO FGH 3 Taking borizontal equillibrium RA FGH + FBH Sino - FBC 15 FGH +9.19Sin(45) FGH =8:5kN tensile