Ea = 54.80KJ/mole
= 54800J/mole
T1 = 285K
T2 =
ln(K2/K1) = Ea/R[ 1/T1- 1/T2]
ln(6/1) = 54800/8.314[ 1/285-1/T2]
1.7917 = 6591.3(0.0035-1/T2)
(0.0035-1/T2) = 1.7917/6591.3
(0.0035-1/T2) = 0.000272
-1/T2 = 0.000272-0.0035
1/T2 = 0.003228
T2 = 1/0.003228
T2 = 309.8K
The temperature = 309.8K >>>>>answer
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