3. The change of entropy of a solid object during heating from 100 K to 200...
Heating Curve for 1 Mole at 1 Atm heating of gas 500 gas 400 heating of lig 300 TK 200 solid I evaporation liquid/ 100+ b L Melning Freezing - Valporization 0 + 100 400 500 200 300 Energy added, kJ Use the heating curve in Model 2 to estimate values for the following parameters of the Assume that the molar mass of the substance is 120 g/mol. a. molar heat of fusion b. molar heat of vaporization c. specific...
A synthetic oil melts at 100 K, boils at 200 K, has a latent heat of fusion of 100 kJ/kg, a latent heat of vaporization of 1 MJ/kg, a solid specific heat of 1000 J/kgK, liquid specific heat of 2000 J/kgK, and vapor specific heat of 3000 J/kgK. Find the final state and temperature if 950 kJ of heat are added to 5 kg of the solid at 90 K.
6. Calculate the entropy change when 2 moles of gaseous water are formed at 100°C and 1 atm from hydrogen and oxygen gas at the same temperature. H2(g) = 130.57 J/K Standard molar entropy: H2O(g) = 188.72 J/K O2(g) = 205.04 J/K Constant volume molar heat capacity: H2O(g) = 25.3 J/ K O 2(g) = 21.1 J/K Constant pressure molar heat capacity: H2O(g) = 33.6 J/K O2(g) = 29.4 JK H2(g) = 20.5 JK H2(g) = 28.8 J/K
+ Heating and Cooling Curves Constants Periodic Table Consider heating solid water (ice) until it becomes liquid and then gas (steam). (Figure 1) Alternatively consider the reverse process, cooling steam until it becomes water and, finally, ice. (Figure 2) In each case, two types of transitions occur, those involving a temperature change with no change in phase (shown by the diagonal line segments on the graphs) and those at constant temperature with a change in phase (shown by horizontal line...
Please help 1. Calculate the increase of entropy (in J/K) when 42 g of ice melts at 0 ºC and 1 atm. (The heat of fusion for ice is 6,000 J/mol.) 2. Calculate the change in entropy (in J/K) when a 34.0 g of water is heated from 12.4 ºC to 70.5 ºC at 1 atm. (The specific heat is 4.184 J/(g-K).) Notice that entropy and heat capacity have the same units.
Part A: An object at 400 K absorbs 25.0 kJ of heat from the surroundings. What is the change in entropy ?S of the object? Assume that the temperature of the object does not change appreciably in the process. Part B: An object at 500 K dissipates 25.0 kJ of heat into the surroundings. What is the change in entropy ?S of the object? Assume that the temperature of the object does not change appreciably in the process.
i got this question wrong. the book previously said that the
units of entropy are J/(mol*K). you can get mol with the grams that
they gave, so why not use it?
Example: If, in a reversible process, 6.66 x 10 J of heat is used to change a 200 g block of ice to water at a temperature of 273 K, what is the change in the entropy of the system? (Note: The heat of fusion of ice = 333...
Question 17 Not yet answered Calculate the increase of entropy (in J/K) when 73 g of ice melts at 0 °C and 1 atm. (The heat of fusion for ice is 6,000 J/mol.) Marked out of 1.00 Answer: P Flag question Calculate the change in entropy (in J/K) when 98.2 g of water is heated from 28.7 °C to 76.7 °C at 1 atm. (The specific heat is 4.184 J/(g-K).) Question 18 Not yet answered Marked out of 1.00 Notice...
The heat capacity of an object is given by the following equation What is the change in the entropy of the object (in J associated with raising its temperature from 290 K to 380 K?
Entropy of naphthalene: Consider naphthalene C10H8 at atmospheric pressure. It is a solid with a melting point at 80.1 degrees Celsius and a boiling point at 218 degrees Celsius. The latent heat of fusion is 19,123 kJ / mol. The molar heat at constant pressure of solid naphthalene has a functional temperature dependence (in K) which is linear. Its value is 0 at T = 0 K and 188.41 J / mol-K at T = 317.15 K. The molar heat...