Can you explain the mechanism for the elimination reaction with 2,3-dibromo-3-phenylpropanoic acid + aqueous NaCo3/H2O to yield beta-bromostyrene.
In protic solvent it will undergo E1 elimination to form beta-bromostyrene
In Protic solvent alpha carbon attached C-Br bond undergo electrolytic cleavage to form carbocation
followed by abstraction acidic proton by base and undergo decarboxylation to form final product.
Can you explain the mechanism for the elimination reaction with 2,3-dibromo-3-phenylpropanoic acid + aqueous NaCo3/H2O to...
The product was 2,3-dibromo-3-phenylpropanoic acid, with a melting point of 198-200 °C . So a racemic mixture of (2R,3S) and (2S,3R). Based on your knowledge of the bromination of alkenes, did this alkene behave like other alkenes, or was the mechanism different than what you expected? (1 pt) ОН NHBrz acetic acid NHBr Br 0 OH Br 2,3-dibromo-3- phenylpropanoic acid pyridinium bromide trans cinnamic acid pyridinium bromide perbromide
Provide the elimination mechanism (with arrows) of the formation of cis-2'-bromostyrene from 2,3-dibromo-3-phenylpropanoic acid in the presence of K2CO3 and the solvent acetone. Also provide the mechanism of KMNO4 on a TLC (thin later chromatography) plate and why colour change occurs
Calculate the theoretical yield of 2,3-dibromo-3-phenylpropanoic acid in 0.7 mmol of trans-cinnamic acid in both mg and mmol.
Can you explain how the J values on HNMR support an E or Z configuration as it relates to the reaction of 2,3-dibromo-3-phenylpropanoic acid with acetone as the solvent, then with water as the solvent, to yield Beta-Bromostyrene. J values for Acetone give a ratio of 1:2 98%-cis 2%-trans. For Water it's 1:4 20%-cis, 80%-trans. Thank you.
Draw the mechanism of the bromination reaction between trans cinnamic acid and bromine. Be sure to include stereochemistry( wedge and dashed structures). The product obtained was the racemic mixture of (2R,3S) and (2S,3R) of 2,3-dibromo-3-phenylpropanoic acid.
Propose a mechanism for the reaction of (2R,3R)-2,3-epoxy-3-methylpentane with 2.1 aqueous acid. Draw the structure of the ring opening product and assign stereochemistry. Is the product optically active? Explain. Hао" Hll "CH-CHз H3C CH3 (6)
Draw a proposed mechanism for the reaction of cyclohexanol with aqueous sulfuric acid to yield cyclohexene. Label each step as either: nucleophilic attack, loss of a leaving group, or proton transfer. What type of elimination reaction is this: E1 or E2? Explain. Explain how the leveling effect has occurred in this reaction? What is the likely base in the last step: water or HSO4-? Explain.
prelab wants me to draw a mechanism for both pairs. so one mechanism for the 93-95 C pair and another mechanism for the 202-204 C pair. Please draw out full mechanism with arrow pushing please for both! trans-cinnamic acid Bromination of trans-cinnamic acid can result in the formation of two different pairs of enantiomers (see Figure 4). Fortunately, the pairs of enantiomers have very different melting points. Thus, we can determine the result of this reaction by examining the melting...
What is Zaitsev’s rule? Give the mechanism for the acid-catalyzed E1 reaction of 2-butanol. Give the mechanism for the base-catalyzed E2 reaction of 2-bromobutane. Draw all possible products. You expect three products from the elimination reaction 2-butanol. What are they? The E2 mechanism is a one-step mechanism. True or False? Explain. Which of these two alcohols would you expect to be more reactive under H3PO4/aqueous conditions? Why? Give the structure of the main product in both cases. 1-phenyl-1-propanol 1 -cyclohexyl-1-propanol...
Hello, I have a question about my post lab report. I used .1g of trans-3-phenyl-2-propanoic acid and 1.5mL of methylene chloride. Later I added 0.8mL of 1M bromine solution to it. I ended up getting the anti stereoisomer of 2,3-dibromo-3-phenylpropanoic acid. The product that I ended up weighing out was 0.0380g. Can you please calculate out the % yield for it? Thanks!