Question

In inductively coupled plasma atomic emission spectrometry the number of atoms excited to a particular energy level is a strong function of temperature. For an element of excitation energy E in joules (J), the measured ICP emission signal S can be written

S = k` e -E/kT

where k` is a constant independent of temperature, T is the absolute temperature in kelvin (K), and k is Boltzmann’s constant (1.3807 × 10–23 J/K ). For an ICP of average temperature 6,500 K and for Cu with an excitation energy of 6.12 ×10-19 J, how precisely does the ICP temperature need to be controlled for the coefficient of variation in the emission signal to be 1% or less?

Answer 1

For icp of average temperature of 6500k for cu results in decrease of cubic content.At longer residence times these extreme temperature cause a loss of cubic phase.The ions formed by ICP discharge are typically positive ions M+ or M+2 .Cu has two isotopes at masses 63 and 65 .ICP detection more than 99% of injected sample goes to the drain less than 1% carried out by plasma.emission spectra from icp contain many lines and these lines overlap to produce continum that arises from recombination of argon ions with electrons.all atoms in sample excited simultaneously which can lead to overlap .icp have background correction .simple background correction involves measuring the background emission intensity away from main peak and substracting this value from total signal measured so icp temperature need to be controlled precisely.