Question

The figure below shows a radio-wave transmitter and a receiver, both h = 41.0 m above the ground and d = 700 m apart. The rec

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Answer #1

distance travelled by wave

D = 2 sqrt ( h^2 + (d/2)^2)

D = 2 * sqrt ( 41^2 + 350^2)

D = 704.786 m

path difference

dL = 704.786 - 700 = 4.786 m

a)

4.786 = L/2

L = 9.573 m

======

b)

also

dL = m L

for m = 1

4.786 = L

======

comment before rate in case any doubt, will reply for sure.. goodluck

> Thanks so much! This works.

John Kennedy Fri, Dec 10, 2021 11:31 AM

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