distance travelled by wave
D = 2 sqrt ( h^2 + (d/2)^2)
D = 2 * sqrt ( 41^2 + 350^2)
D = 704.786 m
path difference
dL = 704.786 - 700 = 4.786 m
a)
4.786 = L/2
L = 9.573 m
======
b)
also
dL = m L
for m = 1
4.786 = L
======
comment before rate in case any doubt, will reply for sure.. goodluck
The figure below shows a radio-wave transmitter and a receiver, both h = 41.0 m above...
1. The diagram below shows the wave crests for two sources that are totally out of phase. For each of the labeled points, determine whether the light intensity (not the wave amplitude) is a minimum or a maximum.2a. (c24p63) Figure P24.63 shows a radio wave transmitter and a receiver, both h = 125 m above the ground and d = 400.00 m apart. The receiver can receive signals both directly, from the transmitter, and indirectly, from signals that bounce off...
> Thanks so much! This works.
John Kennedy Fri, Dec 10, 2021 11:31 AM