Question

Python: Arrays and Lists (do code on repl.it)

Part C (4 points) - more advanced lists You will need a Python repl to solve part C. In Python, define a function named secondHighest which accepts a list of numbers, and returns the second highest number from the list. If the highest value occurs more than once, then it is also the second highest (see example). Assume the input list will always have length at least two (so there is always a second highest value). You might find it helpful to look at the structure of the following function, which returns the smallest of a (non-empty) list of numbers: def smallest(data): ans = data[0] for v in data: if v < ans : ans = v return ans Examples secondHighest([5,3,8,6,2,7,4]) would evaluate to 7 secondHighest([5,3,8,6,2,7,8]) would evaluate to 8 Hint: Keep track of both the highest and second highest value you've seen each time through the loop. ************************************************ STUDENTS SHOULD SUBMIT TO AUTOLAB AFTER

Answer 1

def secondHighest(data):

#assuming 0th element as max and 2nd max

max=data[0]

secondHigh=data[0]

#iterating through list and checking with every element

for i in range(1,len(data)):

if data[i]>max:

secondHigh=max

max=data[i]

else:

if data[i]>secondHigh:

secondHigh=data[i]

return secondHigh

print(secondHighest([5,3,9,6,2,7,4]))

print(secondHighest([1,2,3,4,5]))

https://DryNotableFunction.udaykumar2.repl.run G main.py saved 1 - def secondHighest (data): #assuming oth element as max and 2nd max max=data[@] secondHigh-data[@] Python 3.7.4 (default, Jul 9 2019, 00:06:43) [GCC 6.3.0 20170516] on linux #iterating through list and checking with every element for i in range(1, len(data)): if data[i]>max: secondHigh=max max=data[i] else: if data[i]>secondHigh: secondHigh-data[i] return secondHigh 19 print (secondHighest([5,3,9,6,2,7,4]) print(secondHighest([1,2,3,4,5]))

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