Question

Name, Pre-lab Assignment- Experiment 11 Conservation of Momentum Using the Air Track 1o t becolision ser A,-200 ) is taveling at 3,6 m's and slider B Ms 210 g) is at rest a) (1 pò) What is the total momentum before collision? (Find the momentum of each slider before the collision and then add them together.) b). (I p) After the collision. presume that the sliders move in the same direction with vv m's and vy 3.05 m/s. What is the total momentum following the collision? (Find the 0.398 momentum of each slider after the collision and combine them appropriately.) e). (l pf) what is the total kinetic energy before collision? (Find the kinetic energy of each slider before the collision and add them together.) d). (1 pt) What is the total kinetic energy after collision? e) (2 pts) Is this an elastic collision? Why or why not? (Look in Chapter 7 of the text to find what is meant by an elastic collision. What quantities are conserved in an elastic collision?)

Answer 1

M = mass of body

U = initial velocity of body

V= final velocity of body

(a) initial momentum= initial momentum of A + final momentum of B

= (Ma)(Ua) + (Mb)(Ub)

= (.2)(3.6) + (.21)(0)

= 0.72 kgm

(b) final momentum = final momentum of A + final momentum of B

= (Ma)(Va) + (Mb)(Vb)

= (.2)(.398) + (.21)(3.05)

= 0.0796 + 0.6405

= 0.7201 kgm = 0.72 kgm

(c) kinetic energy before collision= kinetic energy of A + kinetic energy of B

= (1/2)(Ma)(Ua)² + (1/2)(Mb)(Ub)²

= (1/2)(.2)(3.6)² + (1/2)(.21)(0)²

=1.296 J

(d) total kinetic energy after the collision= (1/2)(Ma)(Va)² + (1/2)(Mb)(Vb)²

^{= 0.0158404 + 0.9767625}

^{= 0.9926029 J}

^{(e) no it's not elastic as momentum and kinetic energy both are conserved in elastic collision.}

^{it's an example of inelastic collision as the momentum is conserved but kinetic energy is lost during collision due to inelastic characteristics.}