Question

Conservation of Momentum PHY 121 Lab 10 7) Now seeing what you saw, were you right? What can you say about the momentum before the collision and the momentum after the collision? Final Total Kinetic Energy after the collision: nǐ--%Error_07__ Now change the red cart to being heavier than the blue cart and the blue cart is again initially stationary (0m/s) Initial momentum: 10 N Initial Kinetic Energy: 25 J 8.) Write what you expect to happen to the carts after they collide. Which will be traveling fasterlslower and in what direction? (This will not be graded according to right or wrong. It is just important to write an honest statement as to what you think will happen.) Click start in the upper right cormer. 9.) How right were you in your hypothesis of what you thought would happen? Explain why the carts behaved the way they did after the collision using terms like inertia, force, momentum. Total Momentum after collision: 10-1 N Total Kinetic Energy after the collision: MHL %Error 10-1M& a.mp %Error: 10.) How did the total momentum before the collision of both carts compare to the total momentum after the collision? How did the total kinetic energy before the collision compare to the total kinetic energy after the collision?
0 0
Add a comment Improve this question Transcribed image text
Answer #1

7) mv + 0 = 0 + mv

Total momentum before collisim } = Total momentum after collision.

8 ) Bothe carts are moving along the direction of red cart and lighter one moves faster. Only part of momentum transfers from red to blue cart and blue should have more velocity since its mass is small.

9 ) Blue cart is being at rest before collision

---> Rate of change of momentum is the force,

---> Momentum is conserved. Momentum of red cart decreases and blue cart increases.

10 ) Total momentum before collision = Total momentum after collision

[ Total kinetic energy before collision = Total kinetic energy after collision ] No friction

Totol memenlnm beore Collinor Ota call Both Carts are Amiryaln h moving along on nmoved Prom ved blve ar- s Arm^//. Mo Fe Lelecǐ与 Ameelt, maks call洲m . blue b)no. decvenesant ned and t-erto.fs A¼e carf 一/N。.f..chin

Add a comment
Know the answer?
Add Answer to:
Conservation of Momentum PHY 121 Lab 10 7) Now seeing what you saw, were you right?...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • PART 4: Collisions where the carts make contact but do not stick together 0.250 kg 0.250...

    PART 4: Collisions where the carts make contact but do not stick together 0.250 kg 0.250 kg 0.487 m/s 0.090 m/s Trial 7: In this part we will have the magnets of the blue Both carts same mass cart face the Velcro of the red cart. Because there are no magnets on the Velcro side of the red cart, we'll end up with the plastic of the blue cart hitting Total mass mb of blue cart the Velcro of the...

  • stion 5. Comment on momentum conservation for the inelastie collisions. » u can find patterns in momentum conservat...

    stion 5. Comment on momentum conservation for the inelastie collisions. » u can find patterns in momentum conservation according to whether one carton were moving before the collision, and whether the masses of the carts were ncany or very different. collisions. See if Fone cart or two were nearly equal Question 6. Explain what happens to the momentum in each of the cases. Loo the total momentum is divided un between the two carts after the collisions, compared to how...

  • A 5.0-kg carl (cart 1) rolling cast on a level, frictionless track at 18.0 m/s, collides...

    A 5.0-kg carl (cart 1) rolling cast on a level, frictionless track at 18.0 m/s, collides with a stationary 4.0-kg cart (cart 2). After the collision, cart 1 is still rolling cast, but now at a speed of 2.0 m/s. (a) Assuming the total momentum of the two-cart system is conserved, calculate the final velocity of the second cart. (b) Before the collision, the system's total kinetic energy was 810 J. Calculate the total kinetic energy of the two-cart system...

  • Unsure on all parts of this question Pre-lab Assignment- Experiment 11 Conservation of Momentum Using the...

    Unsure on all parts of this question Pre-lab Assignment- Experiment 11 Conservation of Momentum Using the Air Track 1. Suppose that before collision, slider A (MA-200 g) is traveling at 3.6 m/s and slider B (Ma 210 g) is at rest. a) (1 pt) What is the total momentum before collision? (Find the momentum of each slider befone the collision and then add them together.) b). (1 pt) After the collision, presume that the sliders move in the same direction...

  • Name, Pre-lab Assignment- Experiment 11 Conservation of Momentum Using the Air Track 1o t becolision ser...

    Name, Pre-lab Assignment- Experiment 11 Conservation of Momentum Using the Air Track 1o t becolision ser A,-200 ) is taveling at 3,6 m's and slider B Ms 210 g) is at rest a) (1 pò) What is the total momentum before collision? (Find the momentum of each slider before the collision and then add them together.) b). (I p) After the collision. presume that the sliders move in the same direction with vv m's and vy 3.05 m/s. What is...

  • Impulse and Momentum Name: Date: TA's Name: Learning Objectives: 1. Understanding force ys time curves for...

    Impulse and Momentum Name: Date: TA's Name: Learning Objectives: 1. Understanding force ys time curves for a collision. 2. Calculating impulse using force vs. time curves. 3. Understanding the relationship between impulse and momentum. 4. Applying conservation of momentum for inelastic collisions. Apparatus: Aluminum track, track legs, two smart carts, two cart stops, and small black rectangular cart masses. Part A: Collision of a moving cart with a fixed cart cart 1 Cart stop stationary cart cart stop Consider the...

  • i just need help answering the questions the stuff i put in red is data/ stuff...

    i just need help answering the questions the stuff i put in red is data/ stuff i already answered! please help References Mailing AaBbDd AaBD be AaBbcc Heading? No Spacing Name Prediction: predict that the heavier the cart is it will have the most momentum and kinetic energy before the collision and after the collision because it has the most force. Becks Force-MastAcoletion, more mass equals more force and more force equals more energy Part I - Collision of a...

  • + Conservation of Momentum Ph X Phy 1010-F19-Chapter 6-PH X webassignunet/web/Student/Assignment-Responses/submthdep 219474888tagssautosave C dimension. The system...

    + Conservation of Momentum Ph X Phy 1010-F19-Chapter 6-PH X webassignunet/web/Student/Assignment-Responses/submthdep 219474888tagssautosave C dimension. The system consists of the two objects and the only forces affecting the motion are the internal forces betwoen them during collision. ANALYZE (A) Determine the velocity after collision Because no external force acts, the colligion does not change the total momentum of the system of two particles. We set the total momentum before collision to the total momentum afterward: myVsm (m + m)v The final...

  • 4. Energy and Momentum for 15 points: A 200 gram lab cart is initially at rest...

    4. Energy and Momentum for 15 points: A 200 gram lab cart is initially at rest on top of a 50 cm ramp, as shown. Note that the wheels are very light and the axle has no friction in it. You push the cart as it moves through a distance of 20 cm with a constant force of 10N in a direction oriented 20 degrees below horizontal. After you stop pushing on the cart, it encounters a ramp, and rolls...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT