Question

SLIDING GNOME A force is applied to GNOME a sliding down the plane to stop him Weight force, F Inclined plane Velocity, V 0, slope DATA The coefficient of friction mu = 0.3 The initial velocity (in the shown direction) is Vi = 58.6 ft/s stopping distance S = 28.2 feet USER SUPPLIED DATA FOR THE WEIGHT OF THE GNOME = YOUR WEIGHT + YOUR HEIGHT IN INCHES Example :- suppose your weight is 160 lbf and your height in inches is 170 inches, the weight W = 160 + 170 = 330 lbf FOR THE ANGLE OF SLOPE (IN DEGREES), ADD UP THE DIGITS OF YOUR ACADEMIC PROGRAM Example – suppose I am in Mechanical Engineering, the program code is 0504 – the sum would be 9 and the slope would be 8 degrees. CALCULATE Determine the required force to stop the gnome in the allowed distance Determine the stopping time

please include units

Answer 1

N 2 Initiat to 2 330 cof. ingsine in Ta-going engaso asse weight Q.99 fa UN 0.3x ngus = 0.3x 330x corsº in K.E a work done by force & facer worck by frickson & work by gravity. mez - 0 FxS & fxs Total Change ngs sine. 2802 ssine Fx 28.2 + x 58.6 03* 330x cssºn Ee 330 32.2 > 330x20 58.6 x singo > F 28.05 lexf Net force on body ? F + f - mgsinso F + f - ing sings f >> + gringº 3 m m 2 8.05 0.3*330x cossº + 32.2singt 330 32.2 330 32.2 5.87 ft/32 in upward direction 2 0 using & veutat, (a is opposite of motion direction] - 58.6 - 5.87xt 1 ta q.98 seconds.