Homework Answers
3. open top tank
density of liquid = 1.735*rho ( where rho is density of waqter)
Pressure head = 450 in w.c.
let the level of liquid in inches b e h
p = 450 in wc = 450*rho*g
hence 1.735*rho*g*h = 450*rho*g
h = 259.365 in
4. given
p = 200 in w.c. = 200*rho*g
hence let level of liquid be h
0.873*rho*gh = 200*rho*g
h = 229.095 in
5. specific gravity = 1
Po = 1 psi
h = 10 ft
P = Po + rho*g*h
P = 1 + 0.000036127*386.2205*10*12
P = 2.67435856042 psi
in water column units
P = 0.000036127*386.2205*h = 2.67435856042
h = 191.6692367 in w.c.
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