Draw the structure of the major product formed in the reaction of t-butylcyclohexanone and lithium aluminum hydride. Draw the major product formed in the reaction of t-butylcyclohexanone and lithium tri-sec-butylborohydride.

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Draw the structure of the major product formed in the reaction of t-butylcyclohexanone and lithium aluminum hydride. Draw the major product formed in the reaction of t-butylcyclohexanone and lithium tri-sec-butylborohydride.

Organic-Chemistry

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Answer 1

Answer #1

Li(sec.butyl)3BH is a bulky reducing agent it is difficult for it to attack from the axial side due to steric hindrance of tert. butyl group. Hence it gives the axial hydroxyl product whereas, LiAlH4 gives the equatorial hydroxyl product as major.

answered by: AshMohawk

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Answer 2

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Draw the structure of the major product formed in the reaction of t-butylcyclohexanone and lithium aluminum hydride. Draw the major product formed in the reaction of t-butylcyclohexanone and lithium tri-sec-butylborohydride.

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Draw the structure of the major product formed in the reaction of t-butylcyclohexanone and lithium aluminum hydride. Draw the major product formed in the reaction of t-butylcyclohexanone and lithium tri-sec-butylborohydride.

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Draw the structure of the major product formed in the reaction of t-butylcyclohexanone and lithium aluminum hydride. Draw the major product formed in the reaction of t-butylcyclohexanone and lithium tri-sec-butylborohydride.