A Force F= (6xi+ 5yj), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x direction from the origin to x = 4.69 m.
Find the work W = integral (F
work will be done because of x component of the force.
W = integral 6x dx = 12 *x^2 / 2 = 6 x^2 = 6 X 4.69 X 4.69 = 131.98 J
vector r = 4.69i
now work = Integral of (6xi+ 5yj).4.69i dx = Integral of 28.14 x.dx from 0 to 4.69
W = (28.14 x^2)/2 = 14.07x^2
putting value of x = 4.69
W = 309.48 J
A force F with arrow= (6xi+ 5yj), where F with arrow is in newtons and x and y are in meters, acts on an object as the object moves in the x direction from the origin to x = 5.32 m. Find the work W = the intergral of F with arrow · dr with arrow done by the force on the object.
(a)
A force
F =
(5xî +
4yĵ),
where
F
is in newtons and x and y are in meters, acts
on an object as the object moves in the x-direction from
the origin to
x = 5.21 m.
Find the work W =
F ·
dr done by the force on the object (in
J).
J
(b)
What If? Find the work W
=
F ·
dr done by the force on the object (in J)
if it moves...
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