Solution) d = 0.65 mm = 0.65×10^(-3) m
i = 2.3 uA = 2.3×10^(-6) A
Drift velocity , Vd = ?
i = neA(Vd)
Vd = (i)/(neA)
n = (N/m)(density)
N = avogadro number = 6.023×10^(23)
m = 63.5×10^(-3) kg
Density = 8.9×10^(3) kg/m^3
n = (6.023×10^(23)×8.9×10^(3))/(63.5×10^(-3))
n = 0.844×10^(29)
e = 1.6×10^(-19) C
A = ((pi)(d^2))/(4)
A = ((pi)(0.65×10^(-3))^2)/(4)
A = 0.332×10^(-6) m^2
Vd = (i)/(neA)
Vd = (2.3×10^(-6))/(0.844×10^(29)×1.6×10^(-19)×0.332×10^(-6))
Vd = 5.1×10^(-10) m/s
A. 1x10-10 m/s A 0.65 mm diameter copper wire carries a tiny current of 2.3 uA....
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