Question

A steam turbine operates with P1 = 5 MPa and T1 = 600 °C at the inlet, an exit pressure of P2 = 100 kPa, a mass flow rate of ?̇ = 100 kg/s, and an isentropic efficiency of η = 85%. Complete a thermodynamic analysis of the turbine, using the appropriate data for water, by finding: (A) The temperature at the exit, T2, (B) the work produced by the turbine, ?̇ ?, and (C) the rate of entropy production in the turbine, ?̇ ???. Plot the process on a T-s diagram and clearly label states 1, 2s, and 2.

Problem (1 point): A steam turbine operates with P1= 5 MPa and T1 = 600 °C at the inlet, an exit pressure of P2 = 100 kPa, a mass flow rate of m= 100 kg/s, and an isentropic efficiency of n=85%. Complete a thermodynamic analysis of the turbine, using the appropriate data for water, by finding: (A) The temperature at the exit, T2, (B) the work produced by the turbine, WT, and (C) the rate of entropy production in the turbine, Sgen. Plot the process on a T-s diagram and clearly label states 1, 2s, and 2.

Answer 1

Solutu. givendata. U Steam turbine P=5 MPa. 2 ; d. at the inlet. T-boo's S P2= lookPa, i 10 1g|s. To=?. Niren = 0.85=851. - f TOY Fino @ T=? (exit temperature). (B) Wes produced by turbine (6) Rate of entropy production in turbine. . corresponding to the colores (A) exit temp. find the sp. enthalphy of Steam inlet condition of the steam. P = 5MP, T, = 600 h=3666.5 kJ / kg S;= 7:18'88 retlige.

find the sp. enthalphy of Steem corro 8 fonding to pait pressure. P= 100 kPa hras = 417 44 rolley ngos = 2258.0 ksiKg Sf2s = 1,2025 kJ/kg k Sfgts = 6.0568 killigk. During the isentropic expansion d Si=528 5,= Sfest das sfges e 7.2588 = 1.3025 +225 x 6.0568 | 125 = 0.9834 find the specific enthalphy corresponding to the end point of isentropic expansion. her = has tas hfges - 417.44 +0.9834 * 2258 This = 2637-957 kJ leg?

To find spo enthalphy TL conroxponding to po the efficiency formulae. Nise. = nirhe - ho-hgs 0.85 = 3666.5-he. 3666.5 - 2637.957 The = 2792.24 kolkg || Find the quality of the mit Steam: hg = hf + Mz hfg2 2792.24 = 413:44 + xy (239.2258.0) Tag = 100) I min we got the g quality of steam is 100 and the condition of the steam is dry saturated 50, the from saturated water table, we find temp. Conosponding to prokla and hg=2792.24 He = 198.3ic | b Nork done produced by the turbine Weet = no he = 3666. 6 - 2792.24 = 874.26KJ/KG. Wisentropic = hi-has = 3566-5 - 2637957 = 1028-543 Ksl leg.

VE corrosponding state 2 (0 Change in entory at the to 100kia and Tg = 198.326, S2 - 7.4458 Allegr. change in entropy = Sy-S, = .4458 - 7.2588 ) x100 rds = 1807 kw ,