Question

A) Given The .4H inductor at the left is subject to a current signal at the right: Circuit 2H 3 V(t) 0 1 2 3 B) Determine Step 1: The time expression for the current l(t). Step 2: The time expression for the voltage V(t). Step 3: The sketch of the voltage signal V(t). Step 4: The time expression for the power P(t). Step 5: The sketch of the power signal P(t). Step 6: The time expression for the energy W(t). Step 7: The sketch of the energy signal W(t).

Answer 1

หวก: Allt 11.. 2 Įt for octc i see i (A)= t for lctro i(t)= IA an. L=0.41 Vnitis hd ist de caso olt< 1 Uhld) = 0.4 0(+) -- 014V case 0 <tego ov Wh1t)= 0.4d (1)= AVLIA 0.4

Plt) = V(A) Xi(4) W с оноо<t (4 Pld)? Ou 4x it Case © Plt)- OX 1 = Ow p Pla 0.4 f.en Wla)= s Plaidt waren Out<1 W[= S 0.4% Widja :0.942+c wit)=0 for too o=0:4 t2 + c (co WIA2= out it? Joule .

care 1 <t < 0 Wit)= WIA) yoxdt to Wilo Joule to widlft= 1 = 0.4x x2 = 0.2 Oo D = 0 + c ce002 00: WIALE 002 Joule A Wilt 02 -batt I.