here,
a = 6 * 10^6 m
b = 2 * 10^5 m
b = 0.2 * 10^6 m
the resultant , R = a + b
R = 6 * 10^6 m + 0.2 * 10^6 m
R = 6.2 * 10^6 m
the correct option is (D) 6.2 * 10^6 m
Problem: A spaceship of mass 1.9×106 kg is cruising at a speed of 6.0×106 m/s when the antimatter reactor fails, blowing the ship into three pieces. The first piece, having a mass of 4.9×105 kg , is blown straight backward with a speed of 2.5×106 m/s . A second piece, with mass 7.5×105 kg , continues forward at 1.0×106 m/s. Q: What is the speed of the third piece?
Question 60 If M- $5,000, P= $20, and Q 2,000, then V is 2.0 4.0 6.0 8.0 Question 61
q_1 = 6.0 mc q_3 = 8.0 mc q = +2.0 mc q_2 = -4.0 mc q_4 = -6.0 mc THE 0 calculate vector EF on q due to q_1, q_2, q_3, and q_4
13) A particle (m = 8.0 ug, q = +6.0 nC) has a speed of 80 m/s at point A and moves to point B where the electric potential is 2.0 kV greater than at point A. What is the particle's kinetic energy at point B? Only electric forces act on the particle during this motion. a. 14 J b. 38 uJ c. 10 uJ d. 34 uJ e. 40 uJ
A spaceship of mass 2.0×106 kg is cruising at a speed of 4.9×106 m/s when the antimatter reactor fails, blowing the ship into three pieces. One section, having a mass of 4.6×105 kg , is blown straight backward with a speed of 2.1×106 m/s . A second piece, with mass 8.2×105 kg , continues forward at 1.3×106 m/s . What is the speed of the third piece?
A spaceship of mass 2.3×106 kg is cruising at a speed of 6.0×106 m/s when the antimatter reactor fails, blowing the ship into three pieces. One section, having a mass of 4.7×105 kg , is blown straight backward with a speed of 2.2×106 m/s . A second piece, with mass 7.9×105 kg , continues forward at 1.3×106 m/s .
An object of mass 0.50 kg weighs 2.0 N when it is 1.0 × 106 m above the surface of Planet X. The radius of the planet is 4.0 × 106 m. What free-fall acceleration will the 0.50-kg object experience when at the surface of Planet X? A) 2.0 m/s2 B) 6.3 m/s2 C) 4.0 m/s2 D) 4.8 m/s2
An electron that has a velocity with x component 2.0 x 106 m/s and y component 2.9 x 106 m/s moves through a uniform magnetic field with x component 0.032 T and y component -0.19 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity. answer must be in N units!!!!!!
37- In the diagram below, a 2.0 x 10-6 С charge experiences forces of 3.0 N and 8.0 N at its locatio between charges Q and Q2 Qi 2.0 × 10-1 C F-8.0 N Find the magnitude of the net electric field strength at the location of the 2.0x104 ć charge. A. 2.5x10 N/C B. C. D. 2.8×106 N/C 5.5x106 N/C 1.2x107 N/C
A flat surface with area of 7.00 m2 is oriented at an angle q to a uniform electric field with magnitude 6.0 × 105 N/C. If the flux through this surface is 2.0 × 106 N×m2/C, what is q? 81.8° 32.9° 6.18° 61.6°