An electron that has a velocity with x component 2.0 x 106 m/s and y component 2.9 x 106 m/s moves through a uniform magnetic field with x component 0.032 T and y component -0.19 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity. answer must be in N units!!!!!!
given
vx = 2*10^6 m/s
vy = 2.9*10^6 m/s
Bx = 0.032 T
By = -0.19 T
a) magnetic force, F = q*(v cross B)
= q*( (2*10^6i + 2.9*10^6j) cross (0.032 i - 0.19 j))
= q*(2*10^6*(-0.19) k + 2.9*10^6*0.032*(-k))
= q*(-0.4728*10^6) N
= (-1.6*10^-19)*(-0.4728*10^6) N
= 7.56*10^-14 N (towards +z axis)
b) same. i.e 7.56*10^-14 N (towards -z axis)
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