biven." 5. A car whose mass is 1200kg is traveling on a straight road with a...

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Question

Answer 1

Answer #1

Kinetic energy of any body is given by , K.E. = 1/2(mv^2)

where m = mass of the body

v = velocity of the body

Here m = 1200kg

a) initial velocity= 15m/s

Thus initial kinetic energy = 1/2(1200*15^2) = 135000Joules.

b) final velocity = 35m/s

Thus final kinetic energy = 1/2(1200*35^2) = 735000joules.

c) By work energy theorem net work done is equal to change in kinetic energy.

Thus work done= K.E.(final) - K.E.(initial) = 735000-135000 = 600000Joules.

Answer 2

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