4.2 m/s
you have given the right answer.
In a perfectly elastic collision, the total momentum, as well as the total kinetic energy, is conserved. Whereas in inelastic collision momentum is conserved but the kinetic energy is not conserved.
m1u1 + m2u2 = m1v1 + m2v2
In perfectly elastic collision when the masses of the two bodies are same (m1 = m2) then u1 = v2 and u2 = v1
therefore, m1 = m2 = 2.5Kg and u2 = v1 = 0
m1u1 + m2u2 = m1v1 + m2v2
2.5(4.2) + 2.5(0) = 2.5(0) + 2.5(v2)
v2 = 4.2m/s
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