Question

s uie 4) a) Find the equivalent capacitance for the circuit given, where, Ces uf C2-2 uF,Cs-3 HF. b) Determine the charge on each capacitor and the voltage across each, assuming the battery voltage is V-4v. C2 C1 b C3

Answer 1

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(a) C_2 and C_3 are in parallel. Therefore C_23 = C_2 + C_3 = 5 mu f C_23 and c_1 are in series, So, C_eq = C_23 C_1/C_23 + C_1 = (5 mu f) (5 mu f)/(5 mu f + 5 mu f) = 2.5 mu f (b) charge provided by battery is, Q = c_eq V = (2.5 mu f) 4V = 10 mu c. Therefore charge on C_1 = Q_1 = Q = 10 mu C Voltage across C_1 = V_1 = Q_1/C_1 = 10 mu c/C_1 = 2V Voltage across parallel combination C_2 and C_3 is, V_23 = 4 V - V_1 = 2V . Therefore Charge on C_2 = Q_2 = C_2 V_2 = C_2 (2V) = 4 mu c Charge on C_3 = Q_3 = C_3 V_3 = C_3 (2V) = 6 mu C Voltage on C_2 = Voltage on C_3 = 2V